How do you write the standard form of the equation $y + 4 = - \frac{12}{7} (x - 1)$ $y+4=-12/7(x-1)$ ?

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How do you write the standard form of the equation $y + 4 = - \frac{12}{7} (x - 1)$ $y+4=-12/7(x-1)$ ?

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Answer 1 · 2018-04-16T21:51:48

$7 y + 12 x = - 16$ $7y+12x=-16$

Explanation:

Standard form is $a y + b x = c$ $ay+bx=c$
Start by multiplying everything by $7$ $7$ to get rid of pesky fraction:
$7 y + 28 = - 12 (x - 1)$ $7y+28=-12(x-1)$
Distribute:
$7 y + 28 = - 12 x + 12$ $7y+28=-12x+12$
Than subtract $28$ $28$ over and add the $12 x$ $12x$ over:
$7 y + 12 x = - 16$ $7y+12x=-16$

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How do you write the standard form of the equation $y + 4 = - \frac{12}{7} (x - 1)$ $y+4=-12/7(x-1)$ ?

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Explanation:

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How do you write the standard form of the equation $y + 4 = - \frac{12}{7} (x - 1)$ $y+4=-12/7(x-1)$ ?