How do you solve #\frac { 4} { x - 1} = \frac { 8} { x + 2}#?

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Answer 1 · 2018-04-17T02:54:31

#x=4#

See below.

#color(white)(@@@@@@@@@@@@@@@@@)#
Cross multiply.

#4/(x -1)=8/(x+2)#

You get,

#4(x+2)=8(x-1)#

Now, multiply the terms.

# 4x+8=8x-8#

Bring the #8x# to #color(red)(LHS)# and #8# to #color(red)(RHS)#.

#4x -8x=-8-8#

(Sign changes when the terms are brought to opposite side)

#-4x=-16#

Divide both sides by #-4# .

#x=4#

Hope this helps :)