What is the pH of a 0.003 M KOH solution?

1 Answer
Apr 17, 2018

#pH approx 11.5#

Explanation:

When put in water, the #KOH# dissolves into #K^(+)# and #OH^(-)# ions, with the latter increasing the #pH# of the solution.
As hydroxides can be considered strong bases, it will completely dissociate into the water solution, and form an equal amount of moles of hydroxide ions:

0.003 mol of #OH^(-)#.

Now,

#pOH=-log [OH^(-)]#
#pOH=2.522#

And if we assume this is done under standard conditions:

#pOH+pH=14#
#pH=14-2.522#
#pH approx 11.5#