Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a jack and then, without replacement, another jack?

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fraction or decimal rounded to 4 places

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Answer 1 · 2018-04-17T18:42:34

The probability of drawing two consecutive Jacks without replacement is

1 out of 221 or $1/221$

The probability of drawing the initial Jack is 4 out of 52 as there are 4 Jacks in deck of 52 cards.

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Since you are not replacing the Jack the Deck now has 51 cards and 3 Jacks making that 3 out of 51.

1st Jack = $4/52$

2nd Jack = $3/51$

To find the probability of consecutive events we would multiply the individual probabilities.

$4/52 * 3/51 = 12/(2,652)$

Which reduces to $1/221$