Question

How do you find the value of the discriminant and determine the nature of the roots `-x^2-9=6x`?

Answer 1

`D`=0 and the roots are real and equal.

Explanation:

We have, `x^2+6x+9`=0 [On arrangement]
Thus, `a`=1,`b`=6 and `c`=9
Thus,`D=b^2-4ac`
=`(6)^2-4xx1xx9`
=`36-36`=0
Thus,the roots are real and equal to `x=-3,-3`