How do you solve # 5[x - 4(1 - 2x) - 6] - 3(x +10) = 40x - 12#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Elias Apr 17, 2018 x= 9 Explanation: 1) #5[x-4(1-2x)-6]-3(x=10)=40x-12 # 2) #5[x-4+8x-6]-3(x=10)=40x-12 # Distribute "-4" 3) #5[9x-10]-3(x+10)=40x-12 # Simplify 4) #45x-50-3x-30=40x-12 # Distribute the "5" and "-3" 5) #42x-30=40x-12 # Simplify 6) #2x-30=-12# Subtract 40x to both sides 7) #2x=18 #Add 30 to both sides 8) #x=9# Divide both sides by 2 Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 2292 views around the world You can reuse this answer Creative Commons License