Question

How to find out the derivative of (ln2)^x ?

Answer 1

`f'(x)=ln(ln(2))*ln^x(2)`

Explanation:

`f(x)=ln^x(2)`
because `u=e^ln(u)` and `ln(a^b)=bln(a)`
`f(x)=e^(xln(ln(2))`
Because `(e^(kx))'=ke^(kx)`
`f'(x)=ln(ln(2))e^(xln(ln(2))`
`f'(x)=ln(ln(2))*ln^x(2)`
\0/ here's our answer!