What is the value of $T$ $T$ in the equation: $\frac{1}{T} - \frac{1}{200} = .010$ $1/T - 1/200 = .010$ ?

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Answer 1 · 2018-04-18T14:08:49

See below.

To find the value of $T$ $T$ , we need solve for, or isolate the variable $T$ $T$ .

We do this by using the reverse operations as given in the equation.

Knowing this, we can being to find $T$ $T$ :

$\frac{1}{T} - \frac{1}{200} = 0.010$ $1/T - 1/200 = 0.010$

$\Rightarrow \frac{1}{T} = 0.010 + \frac{1}{200}$ $=> 1/T =0.010 + 1/200$

Here we need to change everything into similar form, so we should now have:

$\Rightarrow \frac{1}{T} = \frac{1}{100} + \frac{1}{200}$ $=> 1/T = 1/100 + 1/200$

Now we need common denominators:

$\Rightarrow \frac{1}{T} = \frac{2}{200} + \frac{1}{200}$ $=> 1/T = 2/200 + 1/200$

Combine:

$\Rightarrow \frac{1}{T} = \frac{3}{100}$ $=> 1/T = 3/100$

From here, all we need to do is cross-multiply:

$\Rightarrow 3 T = 100$ $=> 3T = 100$

Solve for $T$ $T$ :

$\Rightarrow T = \frac{100}{3}$ $=> T=100/3$

What is the value of TT in the equation: 1T−1200=.0101/T - 1/200 = .010?