How do you factor #3x^2+5x+2#?

1 Answer
Apr 19, 2018

the answer is #(x+1)(3x+2)#

Explanation:

you can't take out so you have to multiply the first and second numbers. then you find two numbers that multiply to give you that number and add to give you the middle one. which would be #3,2# so replace #5# with #2,3#
#3x^2+2x+3x+2# now you group and factor#x(3x+2)+1(3x+2)# the #+1# is because there's nothing to take out of #3x+2# so you take out an imaginary #1# and always make sure that the two parenthesis match or you did it wrong