A radioactive isotope $_{Z}^{X} A$ $""_Z^XA$ decay and emits one alpha particle and two beta particles consecutively. How to write the formula for the nuclides produced?

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Answer 1 · 2018-04-19T07:43:48

$_{Z} X^{A} \to_{Z - 2} Y^{A - 4} \to_{Z - 1} U^{A - 4} \to_{Z} X^{A - 4}$ $""_Z X^A to ""_(Z-2) Y^(A-4) to ""_(Z-1) U^(A-4) to ""_Z X^(A-4)$

In alpha decay, the mass number decreases by 4 and the atomic number by 2.

In beta decay, the mass number stays unchanged, the atomic number increases by 1.

A radioactive isotope XZA""_Z^XA decay and emits one alpha particle and two beta particles consecutively. How to write the formula for the nuclides produced?