What is the derivative of #-e^(3x^2)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Shiva Prakash M V Apr 19, 2018 #dy/dx=-6xe^(3x^2)# Explanation: By using chain rule for the function of function concept #y=-e^(3x)^2)# #y=-e^t# #dy/dx=-e^t(dt)/(dx)# #t=3x^2# #t=3u# #u=x^2# #(du)/(dx)=2x# #(dt)/(dx)=3)du)/(dx)# #3(du/(dx)=3xx2x# #(dt)/(dx)=3xx2x# #3xx2x=6x# #(dt)/(dx)=6x# #dy/dx=-e^t(dt)/(dx)# #dy/dx=-e^(3x^2)(6x)# #dy/dx=-6xe^(3x^2)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 28206 views around the world You can reuse this answer Creative Commons License