How do you simplify #sqrt300/sqrt6#?
2 Answers
Explanation:
Apr 19, 2018
Explanation:
#"using the "color(blue)"law of radicals"#
#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#
#•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)#
#rArrsqrt300/sqrt6#
#=sqrt(300/6)=sqrt50#
#sqrt50=sqrt(25xx2)=sqrt25xxsqrt2=5sqrt2#