How do you simplify #sqrt(9200)#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Lucia C. · Stefan V. Apr 19, 2018 The final answer is #20sqrt(23)#. Explanation: #9200# is the product of #400# and #23#, and the square root of #400# is #20#, so it should look something like this: #sqrt(9200)# #sqrt(400⋅23)# #sqrt(400) ⋅ sqrt(23)# #20sqrt(23)# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 3067 views around the world You can reuse this answer Creative Commons License