How much the heat needed to raise the temperature of 700 g of water from 25 c to 90 c?

2 Answers
CrispyRounds
Apr 20, 2018

#Q=190372# J or
#Q approx 190# KJ

Explanation:

To calculate the total heat needed to raise the temperature of 700g of water from 25 C to 90 C you would use the formula

#Q=mcDeltaT#

Where #Q# is heat (Joules), #m# is mass (grams), #c# is the specific heat of the substance (#J/(g*C)#), and #DeltaT# is the change in temperature (Celsius).

Specific heat of water, the energy/heat needed to raise the temperature of 1 gram of water by 1 degree Celsius is 4.184#J/(g*C)#

#DeltaT# is just the change in temperature #90C-25C=65C#

Mass is 700g

From here you just put in each variable and solve for Q:

#Q=700*4.184*65#

#Q=190372# J or
#Q approx 190# KJ

Junaid Mirza
Apr 20, 2018

Approximately #"190.4 kJ"#

Explanation:

Use this equation

#"Q = mC"Δ"T"#

where

  • #"Q ="# Heat
  • #"m ="# Mass of sample
  • #"C ="# Specific heat of sample (#"4.184 J/g°C"# for water)
  • #"ΔT ="# Change in temperature

#"Q" = 700 cancel"g" × "4.184 J"/(cancel"g" cancel"°C") × (90 - 25) cancel"°C" = "190372 J" ≈ "190.4 kJ"#

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