Solve the equation for x : 2sinx+1=1 ?

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Answer 1 · 2018-04-20T02:46:05

#x=npi#

Isolate #sinx:#

#2sinx=1-1#

#2sinx=0#

#sinx=0/2#

#sinx=0#

Examining the unit circle, we see this is true for #x=npi# where #n# is any integer:

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