Question

How do you factor `6x^3-x^2+17=2x^2+47`?

Answer 1

`x^2 (2x - 1) = 10`

Explanation:

Factor
`6x^3−x^2+17=2x^2+47`

1) Subtract `2x^2` from both sides to get all the `x` terms together
`6x^3 - x^2 - 2x^2 + 17 = 47`

2) Subtract `17` from both sides to get all the constants on the same side
`6x^3 - x^2 - 2x^2 = 47 - 17`

3) Combine like terms
`6x^3 - 3x^2 = 30`

4) Divide all the terms on both sides by `3` to reduce the terms
`2x^3 - x^2 = 10`

5) Factor out `x^2`
`x^2 (2x - 1) = 10`