Question

How do you balance `CuCl_2 + Fe -> 2Cu + FeCl_2`?

Answer 1

Like this:

Explanation:

I'd start by looking at what is the most complicated and unbalanced, as we can see there is only 1 `Cu` on the left hand side but there is two `Cu` on the right side.
So add a 2 in front of `CuCl_2`

`2CuCl_2 + Fe ->2Cu+FeCl_2`

But now Chlorine is unbalanced on the left side, as we have 4 on the right, so add a 2 in front of `FeCl_2`

`2CuCl_2 + Fe ->2Cu+2FeCl_2`

Finally balance for iron as that is the only thing left by adding a 2:

`2CuCl_2 +2 Fe ->2Cu+2FeCl_2`

And now it is balanced!