How do you find the zeros, real and imaginary, of #y=-x^2+4x+12# using the quadratic formula?
2 Answers
See a solution process below:
Explanation:
We can use the quadratic equation to solve this problem:
The quadratic formula states:
For
Substituting:
Explanation:
In this case all zeros are real.
A polynomial of degree n has n zeros. Imaginary zeros are always in conjugate pairs.
Remember:
( a polynomial of degree
or
or
For more click here.