How do you find the derivative of #sqrt x^2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Carl S. · Monzur R. Apr 21, 2018 #d/dx[sqrt{x}^2] = d/dx[x] =1# Explanation: We can simplify the expression: #sqrt{x}^2 = x^{0.5 times 2} = x^1 = x# #d/dx[x] = 1# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1487 views around the world You can reuse this answer Creative Commons License