How do you simplify $\frac{4}{\sqrt{4 x} + \sqrt{4 x}}$ $4/(sqrt(4x) + sqrt(4x))$ ?

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Answer 1 · 2018-04-22T01:48:58

$\frac{1}{\sqrt{x}}$ $1/sqrtx$

$\sqrt{4 x} + \sqrt{4 x} = 2 \sqrt{4} x$ $sqrt(4x)+sqrt(4x)=2sqrt4x$

Furthermore, recalling that $\sqrt{a b} = \sqrt{a} \cdot \sqrt{b},$ $sqrt(ab)=sqrta*sqrtb,$

$2 \sqrt{4 x} = 2 (\sqrt{4} \cdot \sqrt{x})$ $2sqrt(4x)=2(sqrt4*sqrtx)$

$\sqrt{4} = 2$ $sqrt4=2$ , so we get

$2 (2 \sqrt{x}) = 4 \sqrt{x}$ $2(2sqrtx)=4sqrtx$

And we end up with

$cancel4/(cancel4sqrtx)=1/sqrtx$

How do you simplify 4/(sqrt(4x) + sqrt(4x))4√4x+√4x4/(sqrt(4x) + sqrt(4x))?