Solve the equation #25log_2x=log_x2# ?
#25log_2x=log_x2#
I have gotten to #logx^25=1/(logx)# but I am not sure how to proceed from here. I am supposed to solve this without the use of a calculator, and the answer is given as #x=2^((+/-)1/5)# . How should I go about solving this?
I have gotten to
2 Answers
I tried this:
Explanation:
I would try changing the base of the second log as:
so we get:
rearrange:
take the square root of both sides to get rid of the square:
apply the definition of log:
Explanation: