Question

If 25mL of a solution of sodium chloride requires 17.9mL of 0.100mol/L silver nitrate for complete reaction what is the molarity of the chloride ion?

Answer 1

`0.0716` M

Explanation:

`NaCl + AgNO_3 = AgCl + NaNO_3`
Mole Ratio of `NaCl` to `AgNO_3` is `1:1`
`Mol_(AgNO3)` = `0.1/(1000/17.9)` = 0.00179 `mol`
`Mol_(NaCl)` = `0.00179` `mol`
`Conc_(Cl^(-))` = `0.00179/(25/1000)`= `0.0716 (mol)/(dm)^3`