How do you solve #2( z - 4) + 3= 5- ( z + 1)#?
2 Answers
Apr 22, 2018
Explanation:
Apr 22, 2018
Explanation:
#"distribute parenthesis on both sides of the equation"#
#2z-8+3=5-z-1larrcolor(blue)"simplify both sides"#
#rArr2z-5=-z+4#
#"add z from both sides"#
#2z+z-5=cancel(-z)cancel(+z)+4#
#rArr3z-5=4#
#"add 5 to both sides"#
#3zcancel(-5)cancel(+5)=4+5#
#rArr3z=9#
#"divide both sides by 3"#
#(cancel(3) z)/cancel(3)=9/3#
#rArrz=3#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left "=2(-1)+3=-2+3=1#
#"right "=5-(4)=1#
#rArrz=3" is the solution"#