How do you solve $12 - 3 + 4 m - 6 (3 m - 2)] = - 7 (2 m - 8) - 3 (m - 2) + 3 m - 5$ $12-3+ 4m - 6( 3m - 2)]= - 7( 2m - 8) - 3( m - 2) + 3m - 5$ ?

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Answer 1 · 2018-04-22T12:09:35

m has no solution.

Expand the brackets:
$12 - 3 + 4 m - 18 m + 12 = - 14 m + 56 - 3 m + 6 + 3 m - 5$ $12-3+4m-18m+12 = -14m+56-3m+6+3m-5$

Group the like-terms:
$21 - 14 m = - 14 m + 57$ $21-14m = -14m+57$

Rearrange to get $m$ $m$ on one side:
$- 14 m + 14 m = 57 - 21$ $-14m+14m = 57-21$

$0 = 36$ $0 = 36$

Since $0 = 36$ $0 = 36$ is a contradiction there is no solution for m which satisfies the equation.

How do you solve 12−3+4m−6(3m−2)]=−7(2m−8)−3(m−2)+3m−512-3+ 4m - 6( 3m - 2)]= - 7( 2m - 8) - 3( m - 2) + 3m - 5?