How do you solve the following system: $- 5 x + 3 y = 6, 8 x - 3 y = 3$ $-5x + 3y= 6, 8x-3y=3$ ?

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Answer 1 · 2018-04-22T12:14:39

$x = 3$ $x = 3$
$y = 7$ $y = 7$

Add the two equations together to cancel the $3 y$ $3y$ and $- 3 y$ $-3y$ :

$- 5 x + 3 y = 6$ $" " -5x + 3y = 6$

$+ (8 x - 3 y = 3)$ $"+ " ( 8x - 3y = 3)$

$\to - 5 x + 8 x + 3 y + (- 3 y) = 6 + 3$ $-> -5x + 8x + 3y + (-3y) = 6 + 3$

$3 x = 9$ $3x = 9$

$x = 3$ $x = 3$

Substitute $x$ $x$ into one of the equations:

$8 x - 3 y = 3$ $8x-3y = 3$

$8 (3) - 3 y = 3$ $8(3)-3y = 3$

$24 - 3 y = 3$ $24 - 3y = 3$

$- 3 y = - 21$ $-3y = -21$

$y = 7$ $y = 7$

How do you solve the following system: -5x + 3y= 6, 8x-3y=3 −5x+3y=6,8x−3y=3-5x + 3y= 6, 8x-3y=3 ?