How do you solve the following system: #-5x + 3y= 6, 8x-3y=3 #? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer sushi · Stefan V. Apr 22, 2018 #x = 3# #y = 7# Explanation: Add the two equations together to cancel the #3y# and #-3y#: #" " -5x + 3y = 6# #"+ " ( 8x - 3y = 3)# #-> -5x + 8x + 3y + (-3y) = 6 + 3# # 3x = 9# # x = 3# Substitute #x# into one of the equations: #8x-3y = 3# #8(3)-3y = 3# #24 - 3y = 3# #-3y = -21# # y = 7# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1490 views around the world You can reuse this answer Creative Commons License