How do you simplify $(a^{- 6}) \cdot \frac{b^{2}}{a^{- 3}} \cdot (b^{8})$ $(a^ -6) * (b^ 2) / (a^ -3) * (b^8)$ ?

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Answer 1 · 2018-04-22T12:20:13

$a^{- 3} . b^{10}$ $a^(-3).b^10$

$\frac{1}{a^{- 3}} = a^{(- 3) . (- 1)} = a^{3}$ $1/a^-3 = a^((-3).(-1)) = a^3$

So ;

$a^{- 6} \cdot \frac{b^{2}}{a^{- 3}} \cdot b^{8} = a^{- 6} \cdot b^{2} . a^{3} \cdot b^{8}$ $a^(-6)*(b^2)/a^(-3)*b^8 =a^(-6)*b^2.a^3*b^8$

= $a^{(- 6 + 3)} . b^{(2 + 8)}$ $a^((-6+3)).b^((2+8))$

= $a^{- 3} . b^{10}$ $a^(-3).b^10$

How do you simplify (a−6)⋅b2a−3⋅(b8)(a^ -6) * (b^ 2) / (a^ -3) * (b^8)?