Question

How do you find the derivative of `f(x)= 1/x^2`?

Answer 1

`f'(x)=-2/x^3`

Explanation:

Rewrite the function with negative exponents, recalling that `1/x^a=x^-a`:

`f(x)=x^-2`

Apply the Power Rule, which tells us that if `f(x)=x^n, f'(x)=nx^(n-1):`

`f'(x)=-2x^(-2-1)`

`f'(x)=-2x^-3`

`f'(x)=-2/x^3`