How do you solve for x in #6 = (4/7)x#?

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Answer 1 · 2018-04-22T21:49:13

#x = 42/4# or #10.5#

#6 = 4/7 x#

#4/7 * 7/4 = 28/28 = 1#

#4/7x * 7/4 = (28x)/28 = 1#

if #4/7x = 6#, then #x = 7/4 * 6#

#7/4 * 6 = (7 * 6)/4#

#= 42/4#

in decimal form, this is #10.5#.