A rectangle has sides measuring $(4 x + 5)$ $(4x +5)$ units and $(3 x + 10)$ $(3x+10)$ units. What is its area?

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A rectangle has sides measuring $(4 x + 5)$ $(4x +5)$ units and $(3 x + 10)$ $(3x+10)$ units. What is its area?

2 Answers

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Answer 1 · 2018-04-23T02:33:28

The area is just length times width: $(4 x + 5) (3 x + 10) = 12 x^{2} + 55 x + 50$ $(4x+5)(3x+10) = 12x^2+55x+50$

Answer 2 · 2018-04-23T02:34:13

$12 x^{2} + 55 x + 50$ $12x^2+55x+50$

Explanation:

the area of a rectangle is: A=length . width
$(4 x + 5) \cdot (3 x + 10)$ $(4x+5)*(3x+10)$
$= 12 x^{2} + 40 x + 15 x + 50$ $=12x^2+40x+15x+50$
$= 12 x^{2} + 55 x + 50$ $=12x^2+55x+50$

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A rectangle has sides measuring $(4 x + 5)$ $(4x +5)$ units and $(3 x + 10)$ $(3x+10)$ units. What is its area?

2 Answers

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

A rectangle has sides measuring (4x+5)(4x +5) units and (3x+10)(3x+10) units. What is its area?

2 Answers

Explanation:

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Impact of this question

A rectangle has sides measuring $(4 x + 5)$ $(4x +5)$ units and $(3 x + 10)$ $(3x+10)$ units. What is its area?