How do you simplify $15 x^{2} + 1 - [4 (x^{2} - 6) + 5]$ $15x^2+1-[4(x^2-6)+5]$ ?

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How do you simplify $15 x^{2} + 1 - [4 (x^{2} - 6) + 5]$ $15x^2+1-[4(x^2-6)+5]$ ?

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Answer 1 · 2018-04-23T02:59:50

$11 x^{2} + 20$ $11x^2+20$

Explanation:

$15 x^{2} + 1 - [4 (x^{2} - 6) + 5]$ $15x^2+1-[4(x^2-6)+5]$

$15 x^{2} + 1 - [4 x^{2} - 24 + 5]$ $15x^2+1-[4x^2-24+5]$

$15 x^{2} + 1 - 4 x^{2} + 24 - 5]$ $15x^2+1-4x^2+24-5]$

$11 x^{2} + 20$ $11x^2+20$

Answer 2 · 2018-04-23T03:00:57

$11 x^{2} - 20$ $11x^2-20$

Explanation:

We go through the inner parenthesis to the outer ones:
$4 (x^{2} - 6) = 4 x^{2} - 24$ $4(x^2-6)=4x^2-24$
$4 x^{2} - 24 + 5 = 4 x^{2} - 19$ $4x^2-24+5=4x^2-19$ $15 x^{2} + 1 - (4 x^{2} - 19) = 15 x^{2} + 1 - 4 x^{2} + 19$ $15x^2+1-(4x^2-19)=15x^2+1-4x^2+19$
$= 11 x^{2} - 20$ $=11x^2-20$

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How do you simplify $15 x^{2} + 1 - [4 (x^{2} - 6) + 5]$ $15x^2+1-[4(x^2-6)+5]$ ?

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How do you simplify 15x2+1−[4(x2−6)+5]15x^2+1-[4(x^2-6)+5]?

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How do you simplify $15 x^{2} + 1 - [4 (x^{2} - 6) + 5]$ $15x^2+1-[4(x^2-6)+5]$ ?