Question

How do you solve `4y^2 - 3(y-4)=4y(y-1)+3y`?

Answer 1

When only one variable is there, an equation can be solved by using simplification and `y=6` in this equation. You can verify it also by putting `y=6` on both sides and the results will be same.

Explanation:

`4y^2-3(y-4)=4y(y-1)+3y`

`4y^2 -3y+12=4y^2-4y+3y " " " " [-3 * (-4)=12, 4y * y=4y^2]`

or

`4y^2-4y^2 -3y +12=-y`

`-3y+12=-y`

So

`12=3y-y`

`2y=12`

`y=12/2`

`y=6`

Hope it helps...