How do you factor #11x^2+122x+11#?

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Answer 1 · 2018-04-23T13:37:32

#11x^2+122x+11 = (11x+1)(x+11)#

Note that #122 = 121+1 = 11^2+1#

Hence we find:

#11x^2+122x+11 = (11x+1)(x+11)#

Answer 2 · 2018-04-23T13:43:46

#(x+11)(11x+1)#

Not much explanation here since 11 is a prime number, there cannot be any other possibilities.