How do you factor $11 x^{2} + 122 x + 11$ $11x^2+122x+11$ ?

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Answer 1 · 2018-04-23T13:37:32

$11 x^{2} + 122 x + 11 = (11 x + 1) (x + 11)$ $11x^2+122x+11 = (11x+1)(x+11)$

Note that $122 = 121 + 1 = 11^{2} + 1$ $122 = 121+1 = 11^2+1$

Hence we find:

$11 x^{2} + 122 x + 11 = (11 x + 1) (x + 11)$ $11x^2+122x+11 = (11x+1)(x+11)$

Answer 2 · 2018-04-23T13:43:46

$(x + 11) (11 x + 1)$ $(x+11)(11x+1)$

Not much explanation here since 11 is a prime number, there cannot be any other possibilities.

How do you factor 11x2+122x+1111x^2+122x+11?