How do you solve $\frac{d}{4} + \frac{d}{3} = 1$ $d/4+d/3=1$ ?

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Answer 1 · 2018-04-23T14:41:10

$d = \frac{12}{7} or 1 \frac{5}{7}$ $d=12/7 or 1 5/7$

$\frac{d}{4} + \frac{d}{3} = 1$ $d/4+d/3=1$

Common Denominator:
$\frac{3 d}{12} + \frac{4 d}{12} = 1$ $(3d)/12 + (4d)/12 =1$

Add:
$\frac{7 d}{12} = 1$ $(7d)/12=1$

Multiply by $12$ $12$ :
$7 d = 12$ $7d=12$

Divide by $7$ $7$ :
$d = \frac{12}{7}$ $d=12/7$

How do you solve d4+d3=1d/4+d/3=1?