How do you solve #4x^2 - 16 = 0#?
2 Answers
Explanation:
- Add
#16# to both sides to get#4x^2=16# - Divide both sides by
#4# to get#x^2=4# - Find the square root of both sides to get
#x = +-2#
Apr 24, 2018
Explanation:
Here, we can take the square root of
Thus,
We can factor a
Setting the factors equal to zero, we get
Hope this helps!