Given #f(x) = (x+3)/2#, what is #f^-1(x)#?

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Answer 1 · 2018-04-24T11:01:07

#f^-1(x)=2x-3#

#y=(x+3)/2#

swap #x,y#

#x=(y+3)/2#

#y=2x-3#

#f^-1(x)=2x-3#

Answer 2 · 2018-04-24T11:02:54

#f^-1(x)=2x-3#

#"let "y=(x+3)/2#

#"rearrange making x the subject"#

#rArrx+3=2y#

#rArrx=2y-3#

#"this is usually expressed in terms of x"#

#rArrf^-1(x)=2x-3#