How do you solve 2x-5y=-19 and 3x+2y =0?

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How do you solve 2x-5y=-19 and 3x+2y =0?

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Answer 1 · 2018-04-24T18:08:25

$y = 3$ $y=3$ and $x = - 2$ $x=-2$

Explanation:

There are multiple ways to solve simultaneous equations. You can use an "elimination" method, where you remove one of the unknown from the equation or use a "substitution" method. I will use a substitution method, where you substitute one variable with an expression containing the other value.

if

$3 x + 2 y = 0$ $3x+2y=0$

then

$y = (\frac{- 3 x}{2})$ $y=((-3x)/2)$

Substitute this value for $y$ $y$ into the other equation:

$2 x - 5 y = - 19$ $2x-5y=-19$

$2 x - 5 (\frac{- 3 x}{2}) = - 19$ $2x-5((-3x)/2)=-19$

$2 x + \frac{15 x}{2} = - 19$ $2x+(15x)/2=-19$

$4 x + 15 x = - 38$ $4x+15x=-38$

$19 x = - 39$ $19x=-39$

$x = - 2$ $x=-2$

So, using any of the two equations we can find $y$ $y$ :

$2 (- 2) - 5 y = - 19$ $2(-2)-5y=-19$

$- 4 - 5 y = - 19$ $-4-5y=-19$

$- 5 y = - 15$ $-5y=-15$

$y = 3$ $y=3$

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How do you solve 2x-5y=-19 and 3x+2y =0?

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