How do you solve this system of equations: $-3x - 5y = 4;- 5x - 4y = 24$ ?

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Answer 1 · 2018-04-25T02:34:57

$x=-8$ , and $y=4$ .

Equation 1

$-3x-5y=4$

Equation 2

$-5x-4y=24$

I'm going to solve this by substitution.

First solve Equation 1 for x.

Equation 3

$x=-(5y+4)/3$

Next, substitute this expression for $x$ into Equation 2

Equation 4

$(5(5y+4))/3-4y=24$

Now solve for $y$ .

$25y+20-12y=72$

$13y=52$

$y=4$

Now put this value for $y$ into Equation 3 to determine $x$ .

$x=-(5(4)+4)/3=-8$

How do you solve this system of equations: -3x - 5y = 4;- 5x - 4y = 24-3x - 5y = 4;- 5x - 4y = 24?