How do you simplify $\frac{\sqrt{16}}{\sqrt{8}}$ $sqrt16/sqrt8$ ?

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How do you simplify $\frac{\sqrt{16}}{\sqrt{8}}$ $sqrt16/sqrt8$ ?

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Answer 1 · 2018-04-26T04:14:43

= $\sqrt{2}$ $sqrt2$

Explanation:

$\frac{\sqrt{16}}{\sqrt{8}}$ $sqrt16/sqrt8$ Multiply the fraction by $1$ $1$ as $\frac{\sqrt{8}}{\sqrt{8}}$ $sqrt8/sqrt8$ :
= $\frac{\sqrt{16 \cdot 8}}{8}$ $sqrt(16*8)/8$ Factor $16$ $16$ and $8$ $8$ :
= $\sqrt{(2 \cdot 2 \cdot 2 \cdot 2)} \cdot (2 \cdot 2 \cdot 2)$ $sqrt((2*2*2*2))*(2*2*2)$ Factor out the three pairs of twos:
= $8 \frac{\sqrt{2}}{8}$ $8sqrt2/8$
= $\sqrt{2}$ $sqrt2$

OR, if you want to do it the simple way:
$\frac{\sqrt{16}}{\sqrt{8}}$ $sqrt16/sqrt8$
= $\sqrt{\frac{16}{8}}$ $sqrt(16/8)$
= $\sqrt{2}$ $sqrt2$
Sorry, forgot you could divide them xD ^^

Answer 2 · 2018-04-26T04:18:47

$\sqrt{2}$ $sqrt2$

Explanation:

Simplify the square roots

$\frac{\sqrt{16}}{\sqrt{8}}$ $sqrt16/sqrt8$ = $\frac{4}{\sqrt{4} \sqrt{2}}$ $4/(sqrt4sqrt2)$ = $\frac{4}{2 \sqrt{2}}$ $4/(2sqrt2)$

Rearrange the equation so there is no square root in the denominator

$\frac{4}{2 \sqrt{2}}$ $4/(2sqrt2)$ ⋅ $\frac{\sqrt{2}}{\sqrt{2}}$ $sqrt2/sqrt2$ = $\frac{4 \sqrt{2}}{2 \cdot 2}$ $(4sqrt2)/(2⋅2)$ = $\frac{4 \sqrt{2}}{4}$ $(4sqrt2)/4$

The fours cancel out and you are left with $\sqrt{2}$ $sqrt2$

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How do you simplify $\frac{\sqrt{16}}{\sqrt{8}}$ $sqrt16/sqrt8$ ?

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