How do you factor $9 b - 16 b^{3}$ $9b - 16b ^ { 3}$ ?

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Answer 1 · 2018-04-26T08:54:56

$b [(3 - 4 b) (3 + 4 b)]$ $b[(3-4b)(3+4b)]$

$9 b - 16 b^{2}$ $9b - 16b^2$

$b (9 - 16 b^{2})$ $b(9 - 16b^2)$

$b (3^{2} - 4 b^{2})$ $b(3^2 - 4b^2)$

$:. b[(3-4b)(3+4b)]$

How do you factor 9b - 16b ^ { 3}9b−16b39b - 16b ^ { 3}?