How do you solve $p^{2} - 2 = - 4$ $p^ { 2} - 2= - 4$ ?

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Answer 1 · 2018-04-26T09:16:07

= $p^{2} = - 4 + 2$ $p^2=-4+2$

= $p^{2} = - 2$ $p^2=-2$

= $p = \pm \sqrt{2 i}$ $p=+-sqrt(2i)$

Hope it helps!

How do you solve p2−2=−4p^ { 2} - 2= - 4?