How do you solve #H= -0.5x^2 + x + 4# using the quadratic formula?

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Answer 1 · 2018-04-26T15:36:37

The answer #x_1=1+sqrt3# and #x_2=1-sqrt3#

show the steps below

#-0.5x^2+x+4=0#

Hit the two side by #-1/0.5#

#x^2-x/0.5-2=0#

#-0.5=-1/2#

#x^2-2x-2=0#

You can solve it by using the law:

#x_1=(-b+sqrt(b^2-4ac))/(2a)#

#x_2=(-b-sqrt(b^2-4ac))/(2a)#

in our formula the values of a b and c equal

#a=1 ,,,,,, b=-2 ,,,,, c=-2#

#x_1=(2+sqrt(4+8))/2#

#x_1=1+sqrt3#

in the same way #x_2# equal

#x_2=1-sqrt3#