Question

Derivative of y=e^x\lnx ?

Answer 1

Quotient rule:
`f/g=(f'*g -g'*f)/(g^2)` where `g!=0`

Explanation:

`y=e^x/ln(x)`
`f=e^x => f'=e^x`
`g=ln(x) => g'=1/x`
`y'=(e^x*ln(x)-1/x * e^x)/(ln(x)^2)=e^x(ln(x)-1/x)/(ln(x)^2)`