50.0 mL of a 0.269 M NaCl (aq) contain how many grams of solute?

1 Answer
zhirou
Apr 27, 2018

#"0.789 g"#.

Explanation:

First, we'll need to find the number of moles of #"NaCl"# in #"50.0 mL"# of a #"0.269 M"# solution.

Molarity is defined as the number of moles per liter, so we can use that to determine the number of moles in #"50.0 mL"# (#"0.0500 L"#):

#"0.269 mol"/"1L" = "0.269 × 0.0500 mol"/"0.0500 L" = "0.0135 mol"/"0.0500 L"#

Then, we can use the molar mass of #NaCl# to find the mass of #0.0135# moles of it:

#"mass" = "0.0135 mol" xx "(22.99 + 35.45) g/mol"#
#= "0.0135 mol" xx "58.44 g/mol" = "0.789 g"#

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