Factorise #x²+7xy+12y²# ?
2 Answers
Apr 27, 2018
See the answer below...
Explanation:
#x^2+7xy+12y^2#
#=x^2+3xy+4xy+12y^2" "#
#=x(x+3y)+4y(x+3y)#
#=color(red)(ul(bar(|color(green)((x+3y)(x+4y))|# [It is called middle term factor process of factorization.]
Here, you have to break the middle factor in such a way that the the product of the formers will be equal to the products of the co-efficient of the first and last term with sign.
Hope it helps...
Thank you...
:-)
Apr 27, 2018
Explanation:
#"this can be factored in the same way as a quadratic"#
#"in one variable"#
#"the factors of + 12 which sum to + 7 are + 3 and + 4"#
#rArrx^2+7xy+12y^2=(x+3y)(x+4y)#