How do you solve #3g ^ { 2} - 8= 0#?

2 Answers
Apr 28, 2018

the answer is #g=+-(2sqrt(2))/(sqrt(3))#

Explanation:

first add #8# to both side and to get rid of #^2#, you have to do the opposite like nay other which is square root. and so you'll get #g=sqrt(8/3)# and you can simplify #8# to #2sqrt(2)# and and #3# can't be simplified so you leave it alone and there you go

Apr 28, 2018

#g=(+-2sqrt2)/(sqrt3)#

Explanation:

Given: #3g^2-8=0#.

Add #8# to both sides.

#3g^2-color(red)cancelcolor(black)8+color(red)cancelcolor(black)8=0+8#

#3g^2=8#

Divide by #3# on both sides.

#(color(red)cancelcolor(black)3g^2)/(color(red)cancelcolor(black)3)=8/3#

#g^2=8/3#

Square root both sides to get #g#.

#g=+-sqrt(8/3)#

#=+-(sqrt8)/(sqrt3)#

#=(+-2sqrt2)/(sqrt3)#