How many moles of NaOH are present in 26,5 mL of 0.190 M NaOH?

Question

2069 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-28T12:38:47

$"0.00504 mol"$ .

$"0.190 M"$ $NaOH$ means that, for every $1$ liter of $NaOH$ , there will be $0.190$ moles:

$"0.190 mol"/"1L"$

So, using this ratio, we can find how many moles of $NaOH$ there are in $"26.5 mL"$ , or $"0.0265 L"$ :

$"0.190 mol"/"1L" = "0.190 × 0.0265 mol"/"0.0265 L" = "0.00504 mol"/"0.0265 L"$

Answer 2 · 2018-04-28T12:45:14

0.00504

Concentration = moles of solute / volume of solution.

$sf(c=n/v)$

$:.$ $sf(n=cxxv)$

$:.$ $sf(n_(NaOH)=0.0190xx26.5/1000=0.00504)$

2 points to note: