Question

How do I prove this trigonometric identity?

`cos^2beta/(1-sinbeta)=1+sinbeta`

Answer 1

`cos^2beta/(1-sinbeta)=1+sinbeta`

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Multiply and divide by `1+sinbeta`

`=>(cos^2beta(1+sinbeta))/((1-sinbeta)(1+sinbeta))`

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`=>(cos^2beta(1+sinbeta))/(1-sin^2beta)`

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`=>(cancelcos^2beta(1+sinbeta))/cancel(cos^2beta`
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`->1+sinbeta`