Can anyone please help me answer the question in the picture?

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Can anyone please help me answer the question in the picture?

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Answer 1 · 2018-04-29T12:01:00

Apply Pythagoras rule .

${perpendicular}^{2} + {base}^{2} = {hypotenuse}^{2}$ $"perpendicular"^2+"base"^2="hypotenuse"^2$

Explanation:

${perpendicular}^{2} + {base}^{2} = {hypotenuse}^{2}$ $"perpendicular"^2+"base"^2="hypotenuse"^2$

Here,

$perpendicular = b$ $"perpendicular"=b$

$base = ? (x)$ $"base"=?(x)$

$hypotenuse = 2 b$ $"hypotenuse"=2b$

Hence,

$b^{2} + x^{2} = {(2 b)}^{2}$ $b^2+x^2=(2b)^2$

$\Rightarrow b^{2} + x^{2} = 4 b^{2}$ $=>b^2+x^2=4b^2$

$\Rightarrow x^{2} = 3 b^{2}$ $=>x^2=3b^2$

$\Rightarrow x = \sqrt{3} \cdot b$ $=>x=sqrt3 cdot b$

The length of base is $\sqrt{3} \cdot b$ $color(red)(sqrt3 cdot b$ unit.

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Can anyone please help me answer the question in the picture?

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