What is the equation of the line between $(0, 0)$ $(0,0)$ and $(2, - 10)$ $(2,-10)$ ?

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What is the equation of the line between $(0, 0)$ $(0,0)$ and $(2, - 10)$ $(2,-10)$ ?

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Answer 1 · 2018-04-29T13:28:41

The slope is -5.

Explanation:

To find this answer, we'll be using the point slope formula:

$\frac{Y_{2} - Y_{1}}{X_{2} - X_{1}} = m$ $(Y_2 - Y_1)/(X_2 - X_1) = m$ , where $m$ $m$ is the slope.

$(0, 0)$ $(0, 0)$ $(X_{1}, Y_{1})$ $(X_1, Y_1)$
$(2, 10)$ $(2, 10)$ $(X_{2}, Y_{2})$ $(X_2, Y_2)$

Now, plug-in the variables:

$\frac{- 10 - 0}{2 - 0}$ $(-10 - 0)/(2-0)$ = $m$ $m$

Subtract.

$- \frac{10}{2}$ $-10/2$ = $m$ $m$

Simplify.

$- \frac{5}{1}$ $-5/1$ = $m$ $m$

The slope is $- 5$ $-5$ .

$(y = - 5 x)$ $(y = -5x)$

Answer 2 · 2018-04-29T14:04:47

$y = - 5 x$ $y=-5x$

Explanation:

Slope-intercept form of an equation: $y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the y-intercept

Let's first find the slope using the points $(x_{1}, y_{1})$ $(x_1, y_1)$ and $(x_{2}, y_{2})$ $(x_2, y_2)$ : $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$

$\frac{- 10 - 0}{2 - 0}$ $(-10-0)/(2-0)$

$\frac{- 10}{2}$ $(-10)/2$

$- 5$ $-5$

Our equation is currently $y = - 5 x + b$ $y=-5x+b$

The y-intercept is in the format $(0, b)$ $(0, b)$ . The point $(0, 0)$ $(0, 0)$ is the y-intercept in this case.

$y = - 5 x + 0$ $y=-5x+0$

$y = - 5 x$ $y=-5x$

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What is the equation of the line between $(0, 0)$ $(0,0)$ and $(2, - 10)$ $(2,-10)$ ?

2 Answers

Explanation:

Explanation:

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What is the equation of the line between $(0, 0)$ $(0,0)$ and $(2, - 10)$ $(2,-10)$ ?