Solve this? $12 x^{2} - 7 x - 12 = 0$ $12x^2 - 7x - 12=0$

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Answer 1 · 2018-04-30T04:01:23

$x = - \frac{3}{4}$ $x = -3/4$ and $x = \frac{4}{3}$ $x=4/3$

We begin by factoring the trinomial $12 x^{2} - 7 x - 12 = 0$ $12x^2-7x-12=0$

The factors of the 12 are 4 and 3.

$4 \cdot - 4 = - 16$ $4*-4 =-16$
$3 \cdot 3 = 9$ $3*3=9$
$- 16 + 9 = 7$ $-16+9=7$

$(4 x + 3) (3 x - 4) = 0$ $(4x+3)(3x-4) = 0$

Now set both binomial factors equal to zero and solve.

$4 x + 3 = 0$ $4x+3=0$
$4 x = - 3$ $4x=-3$
$x = - \frac{3}{4}$ $x=-3/4$

$3 x - 4 = 0$ $3x-4=0$
$3 x = 4$ $3x=4$
$x = \frac{4}{3}$ $x=4/3$

Solve this? 12x^2 - 7x - 12=012x2−7x−12=012x^2 - 7x - 12=0